How do you graph $y=sin(x+pi)$ ?

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Answer 1 · 2018-02-23T19:09:08

We start by rewriting using identities.

$y = sin(x + pi)$

$y = sinxcos(pi) + sin(pi)cosx$

$y = sinx(-1) + 0$

$y = -sinx$

This is the graph of the basic sine function with a reflection over the x-axis.

graph{y = -sinx [-10, 10, -5, 5]}

Hopefully this helps!

How do you graph y=sin(x+pi)y=sin(x+pi)?