How do you graph $y= ((sqrt 3/2)sin(x)) + (.5cos(x))$ ?

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Answer 1 · 2018-03-25T03:50:09

The given equation

$y= ((sqrt 3/2)sin(x)) + (.5cos(x))$

$=> y= cos(pi/6)sin(x) + sin(pi/6)cos(x))$

$=> y=1*sin(x +pi/6)$
The above relation obviously is a periodic sine function of $x$ with amplitude $1$ and initial phase angle $phi=pi/6$

so the graph will be as follows

drawn drawn

How do you graph y= ((sqrt 3/2)sin(x)) + (.5cos(x)) y= ((sqrt 3/2)sin(x)) + (.5cos(x))?