How do you graph $y = {(x - 12)}^{2} - 7$ $y= (x-12)^2 -7$ ?

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Answer 1 · 2015-08-29T04:51:24

Simplify the function
y = $x^{2} - 24 x + 137$ $x^2 - 24x +137$

Find its vertex

x = $\frac{- b}{2 a} = \frac{24}{2}$ $(-b)/(2a) = 24/2$ = 12

Take a few points on both sides of 12

x : y
9 : 2
10 : -3
11 : -6
12 : -7
13 : -6
14 : -3
15 : 2
16 : 9

Polt the points and join them with a smooth line
graph{x^2-24x+137 [-20.27, 20.29, -10.14, 10.13]}

How do you graph y=(x−12)2−7y= (x-12)^2 -7 ?