How do you graph y=−x2+2x+3?

1 Answer
bp
Jun 19, 2016

Explained below

Explanation:

The given function is a quadratic function , which would represent a parabola. Hence it would be prudent to put it in the vertex form.

It would be y=−(x2−2x)+3

That is y = −(x−1)2+4

This shows that vertex is (1,4) and axis of symmetry is x=1. The parabola would open downwards because the coefficient of x2 is negative. y -intercept would be 3 and x intercepts would be -1 and 3. With all this information available, the parabola can be easily graphed.[For x intercepts put y=0 and factorise #-x^2 +2x-3=0]

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