How do you graph $y= x^2+5$ ?

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Answer 1 · 2018-03-03T09:03:18

The graph looks like this
graph{x^2 + 5 [-14.1, 14.37, -1.99, 12.25]}

$y = x^2 + 0x + 5$ , compared with the general form of parabola function $ax^2 + bx + c, a = 1, b = 0, c = 5$
It is a U shaped a parabola as a > 0.

x vertex: $= -b/(2a) =(-0)/2 = 0$
y $= 0 + 5 = 5$
$"Vertex": (0, 5)$

Two points:
$x = 1$ : $y = 1^2 + 5 = 6 => (1, 6)$
$x = -1$ : $y = (-1)^2 + 5 = 6 => (-1, 6)$

Find the three points and the graph looks like this https://www.desmos.com/calculator/qwjal4zmxo

How do you graph y= x^2+5 y= x^2+5 ?