How do you graph y = (x+3)^2-1y=(x+3)2−1?

1 Answer
Meave60
Aug 26, 2015

Find the vertex and axis of symmetry. Plot the vertex. Determine points on both sides of the axis of symmetry. Plot the points. Sketch a curve to represent the parabola. Do not connect the points.

Explanation:

y=(x+3)^2-1y=(x+3)2−1 is in the vertex form of a parabola, y=a(x-h)-1y=a(x−h)−1, where h=-3 and k=-1h=−3andk=−1.

First find the vertex. The vertex of the parabola is the point (h,k)=(-3,-1)(h,k)=(−3,−1). This is the highest or lowest point on the parabola.

Next find the axis of symmetry. The is the line x=h=-3x=h=−3. This is the line that separates the two halves of the parabola into mirror images.

![https://www.mathsisfun.com/algebra/http://quadratic-equation-graphing.html](https://useruploads.socratic.org/IE5Et4YlTci6QaCBq3Qr_quadratic-vertex.gif)

Now determine some points on both sides of the axis of symmetry by substituting values for xx in the equation. Plot the vertex and the points. Sketch a graph that is a curved parabola. Do not connect the dots.

x=-5,x=−5, y=3y=3
x=-4,x=−4, y=0y=0
x=-2,x=−2, y=0y=0
x=-1,x=−1, y=3y=3

graph{y=(x+3)^2-1 [-10, 10, -5, 5]}

Related questions
See all questions in Quadratic Functions and Their Graphs
Impact of this question
12335 views around the world
You can reuse this answer
Creative Commons License