How do you graph $y=(x-4)^2$ by plotting points?

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Answer 1 · 2017-08-08T02:56:45

Refer to the explanation for the process.

Graph:

$y=(x-4)^2$

This is a quadratic equation in vertex form: $y=a(x-h)^2+k$ , where $k=0$ , and the graph will be a parabola.

Choose values for $x$ and solve for $y$ . These will be your points.

$x=0,$ $y=16$

$x=1,$ $y=9$

$x=2,$ $y=4$

$x=3,$ $y=1$

$x=4,$ $y=0$

$x=5,$ $y=1$

$x=6,$ $y=4$

$x=7,$ $y=9$

$x=8,$ $y=16$

There are 9 points. Plot them on a grid and sketch a parabola through the points.

graph{y=(x-4)^2 [-14.71, 17.32, -3.1, 12.92]}

How do you graph y=(x-4)^2 y=(x-4)^2 by plotting points?