How do you graph #y=-x+6# by plotting points?

1 Answer

Pick a few values for #x# (I would suggest ones that make #y=-x+6# easy to evaluate).
Plot the resulting #(x,y)# value pairs on the Cartesian plane.
Draw line through the points.

Explanation:

For example, choosing #x in {-1,0,+1}#
gives
#color(white)("XXX"){: (ul(x),color(white)("XX"),ul(y=-x+6)), (-1,,7),(0,,6),(+1,,5) :}#
results in the pairs:
#color(white)("XXX")(-1,7), (0,6), (1,5)#

Plotting these and drawing a line through these points should look like:
enter image source here