How do you identify $\frac{cot (\frac{π}{2} - u)}{cos u}$ $cot(pi/2-u)/cosu$ ?

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How do you identify $\frac{cot (\frac{π}{2} - u)}{cos u}$ $cot(pi/2-u)/cosu$ ?

1 Answer

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Answer 1 · 2017-04-06T16:09:08

$tan u sec u$ $tan u sec u$

Explanation:

$\frac{cot (\frac{π}{2} - u)}{cos u} = \frac{tan u}{cos u} = tan u \cdot \frac{1}{cos u} = tan u sec u$ $cot (pi/2 - u)/cos u = tan u / cos u = tan u * 1/ cos u = tan u sec u$

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How do you identify $\frac{cot (\frac{π}{2} - u)}{cos u}$ $cot(pi/2-u)/cosu$ ?

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