Question

How do you identify `(tanx+1)^2cosx`?

Answer 1

`(tanx+1)^2cosx=secx+2sinx`

Explanation:

`(tanx+1)^2cosx`

= `(tan^2x+2tanx+1)cosx`

= `(sec^2x+2tanx)cosx`

= `(secx xx1/cosx+2sinx/cosx)cosx`

= `secx+2sinx`