How do you identify the important parts of $y=(x-2)^2$ to graph it?

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Answer 1 · 2015-10-02T01:02:50

Vertex is $(2,0)$
Axis of symmetry $x=2$

$y=(x-2)^2$

It is a quadratic function in vertex form
$y = a(x-h)+k$
Where -
$(h,k)$ is vertex
$x=h$ is axis of symmetry.

In our case there is no $k$ term. We shall have it as $0$

$y=(x-2)^2+0$

Co-ordinates of the vertex

$x=-1(h) = -1(-2)=2$
$y=k=0$

Vertex is $(2,0)$
Axis of symmetry $x=2$

Since $a$ is positive, the curve is concave upwards.
It has a minimum.

How do you identify the important parts of y=(x-2)^2y=(x-2)^2 to graph it?