How do you identify the important parts of y = x^2 + x + 1 to graph it?

1 Answer
Dec 23, 2016

Vertex at (-1/2,3/4)
Y intercept at (0,1)
No x intercepts graph{x^2+x+1 [-10, 10, -5, 5]}

Explanation:

y=x^2+x+1

Vertex:
Complete the square into vertex form y=a(x-h)+k
y=(x+1/2)^2+3/4

Intercepts:
The y intercept is at (0,1). We know this because if we plug in 0 in for x, the output is 1.

There are no x intercepts because the parabola is facing up and has a vertex above the x axis.