Question

How do you integrate `(4x+7)/(2x+5) dx`?

Answer 1

Simple math ! `=>`

`int(4x+7)/(2x+5) dx= 2int(4x+7)/(4x+10)dx = 2int(4x+10-3)/(4x+10)dx`

`2int1dx-3int1/(4x+10) dx= 2int1dx-3/2int2/(2x+5)dx`

`[2x]-3/2[ln(2x+5)]+C`