How do you integrate by parts: int x e^3xdx?

1 Answer
Jun 9, 2015

This seems to be:

int xe^(3x)dx

e^3(x) wouldn't make sense (e is a constant, not a function), and e^3x ne (ex)^3 (improper implications from trig^n(x) = (trigx)^n). e^(x^3) would be very advanced to integrate, and would not be remotely easy by integration by parts. x^2e^3 would be way too simple.

Assuming so...

Let:
u = x
du = 1dx
dv = e^(3x)dx
v = 1/3e^(3x)

= uv - intvdu

= x/3e^(3x) - 1/3inte^(3x)dx

= x/3e^(3x) - 1/3[1/3e^(3x)] + C]

= x/3e^(3x) - 1/9e^(3x) + C

or

= e^(3x)/9 (3x - 1) + C