How do you integrate $intsqrt(9-x^2)(-2x)dx$ ?

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Answer 1 · 2017-01-21T15:47:31

Let $u = 9 - x^2$ . Then, by the power rule, $du = -2xdx$ and $dx = (du)/(-2x)$ .

$=intsqrt(u)(-2x) * (du)/(-2x)$

$=intsqrt(u)du$

$=u^(3/2) + C$

$=2/3(9 - x^2)^(3/2) + C$

Hopefully this helps!

How do you integrate intsqrt(9-x^2)(-2x)dxintsqrt(9-x^2)(-2x)dx?