How do you integrate int (5x+4)^5 using substitution?

2 Answers
Douglas K.
Oct 31, 2016

Please see the explanation.

Explanation:

Let u = 5x + 4, then du = 5dx or dx = (1/5)du

int(5x + 4)^5dx = (1/5)intu^5du = u^6/30 + C

Reverse the substitution:

int(5x + 4)^5dx = (5x+4)^6/30 + C

Douglas K.
Oct 31, 2016

Please see the explanation.

Explanation:

Let u = 5x + 4, then du = 5dx or dx = (1/5)du

int(5x + 4)^5dx = (1/5)intu^5du = u^6/30 + C

Reverse the substitution:

int(5x + 4)^5dx = (5x+4)^6/30 + C

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