How do you integrate x2ex2dx using integration by parts?

1 Answer
Apr 30, 2016

See the explanation section below.

Explanation:

To integrate x to a power times e to a power, we expect to differentiate the x and integrate the e to a power

x2ex2dx

In order to integrate ex2dx we need an x so that we can use substitution.

x2ex2dx=xex2xdx .

Let u=x and dv=ex2xdx

The du=1dx and v=12ex2

x2ex2dx=12xex212ex2dx.

Now we need to stop.

ex2dx has no closed form solution using elementary functions. The integral has a name and some series approximations, but that's the best we can do.

You can read more about it here at Wolfram and here at Wikipedia