How do you integrate ln x / x^(1/2)lnxx12?

1 Answer
Jul 5, 2016

= 2 sqrt x ln x - 4 sqrt x + C=2xlnx4x+C

Explanation:

Use IBP

int u v' = uv - int u'v

here

u = ln x, u' = 1/x
v' = x^{-1/2}, v = 2 x^{1/2}, using the power rule

so we have

2 sqrt x ln x - 2 int dx qquad 1/x sqrt x

= 2 sqrt x ln x - 2 int dx qquad x^{-1/2}

= 2 sqrt x ln x - 2*x^{1/2}/(1/2) + C

= 2 sqrt x ln x - 4 sqrt x + C