Question

How do you integrate `sinh2xe^(cosh2x) dx`?

Answer 1

The answer is: `1/2e^cosh(2x)+c`.

`intsinh2xe^cosh(2x)dx=1/2int2sinh2xe^cosh(2x)dx=1/2e^cosh(2x)+c=`.

This is because:

`inte^f(x)*f'(x)dx=e^f(x)+c`.