How do you integrate x^2 e^-xx2e−x? Calculus Techniques of Integration Integration by Parts 1 Answer Konstantinos Michailidis Oct 26, 2015 It is int x^2*e^-xdx=-e^-x*x^2+int e^-x2xdx=-x^2*e^-x-2x*e^-x+2*int e^-xdx=-e^-x*(x^2+2x+2)+c∫x2⋅e−xdx=−e−x⋅x2+∫e−x2xdx=−x2⋅e−x−2x⋅e−x+2⋅∫e−xdx=−e−x⋅(x2+2x+2)+c We used integration by parts int f'(x)*g(x)dx=f(x)*g(x)-intf(x)*g'(x)dx Answer link Related questions How do I find the integral int(x*ln(x))dx ? How do I find the integral int(cos(x)/e^x)dx ? How do I find the integral int(x*cos(5x))dx ? How do I find the integral int(x*e^-x)dx ? How do I find the integral int(x^2*sin(pix))dx ? How do I find the integral intln(2x+1)dx ? How do I find the integral intsin^-1(x)dx ? How do I find the integral intarctan(4x)dx ? How do I find the integral intx^5*ln(x)dx ? How do I find the integral intx*2^xdx ? See all questions in Integration by Parts Impact of this question 1649 views around the world You can reuse this answer Creative Commons License