Question

How do you multiply `((0, 6), (5, -5))` and `((1, 1, 1), (0, 0, -2))`?

Answer 1

`C_color(blue)(23) =((0,6),(5,-5)) * ((1,1,1),(0,0,-2)) = ((0,0,-12),(5,5,15))`

Explanation:

to multiply a matrix by another matrix we need the number of columns to match the number of rows.
`C_(ik)=A_(icolor(red)1)B_(color(red)1k)-A_(icolor(red)2)B_(color(red)2k)+cdots+ A_(icolor(red)N)B_(color(red)Nk)`
note the inner counter, `color(red)j` is the same that is the column of A is equal to the row of B ...
`C_(ik) =sum_(j=1)^NA_(icolor(red)j) B_(color(red)jk)`
`((c_(11),c_(12), cdots,c_(1k)), (vdots,vdots, vdots, vdots), (c_(k1),c_(k2), cdots, c_(kk)))= ((a_(11),a_(12), cdots,a_(1j)), (vdots,vdots, vdots, vdots), (a_(i1),a_(i2), cdots, a_(ij))) * ((b_(11),b_(12), cdots,b_(1k)), (vdots,vdots, vdots, vdots), (b_(j1),b_(j2), cdots, b_(jk)))`

Now that we had a quick review on Matrix multiplication in you case: `A_(2color(red)2) = ((0,6),(5,-5)); B_(color(red)(2)3)=((1,1,1),(0,0,-2))`
So the multiplication order is:
`C_color(blue)(23) = A_(color(blue)2color(red)2)*B_(color(red)(2)color(blue)(3)`
`C_color(blue)(23) =((0,6),(5,-5)) * ((1,1,1),(0,0,-2)) = ((0,0,-12),(5,5,15))`