How do you multiply $((2, 8), (6, 3))$ with $((3, 0), (2, -1))$ ?

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Answer 1 · 2017-07-04T17:44:51

$((a_11, a_12),(a_21, a_22))$

The product is $A$ .

$a_11 = 2 * 3 + 8 * 2$
$a_12 = 2 * 0 + 8(-1)$
$a_21 = 6 * 3 + 3 * 2$
$a_22 = 6 * 0 + 3(-1)$

$A = ((22, -8),(24, -3))$

How do you multiply ((2, 8), (6, 3))((2, 8), (6, 3)) with ((3, 0), (2, -1))((3, 0), (2, -1))?