How do you multiply $(2 x - 8) (2 x - 8)$ $(2x - 8) ( 2x - 8)$ ?

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Answer 1 · 2018-04-12T01:49:36

$4 x^{2} - 32 x + 64$ $4x^2-32x+64$

$(2 x - 8) (2 x - 8)$ $(2x-8)(2x-8)$
$4 x^{2} - 16 x - 16 x + 64$ $4x^2-16x-16x+64$
$4 x^{2} - 32 x + 64$ $4x^2-32x+64$

How do you multiply (2x−8)(2x−8)(2x - 8) ( 2x - 8)?