How do you multiply $\frac{30 a^{2}}{18 b} \cdot \frac{6 b}{5 a}$ $(30a^2)/(18b)*(6b)/(5a)$ ?

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Answer 1 · 2015-04-09T16:37:53

The answer is $2 a$ $2a$ .

Multiply both numerators and both denominators, then simplify.

$\frac{30 a^{2}}{18 b} \cdot \frac{6 b}{5 a}$ $(30a^2)/(18b)*(6b)/(5a)$ =

$\frac{180 a^{2} b}{90 a b}$ $(180a^2b)/(90ab)$ =

Reduce $\frac{180}{90}$ $180/90$ to $2$ $2$ =

$\frac{2 a^{2} b}{a b}$ $(2a^2b)/(ab)$ =

Reduce $\frac{a^{2}}{a}$ $a^2/a$ to $a$ $a$ .

$\frac{2 a b}{b}$ $(2ab)/(b)$ =

Cancel the b in the numerator and denominator.

$(2acancel(b))/(cancel(b))$ =

$2a$

How do you multiply (30a^2)/(18b)*(6b)/(5a)30a218b⋅6b5a(30a^2)/(18b)*(6b)/(5a)?