How do you multiply $(3t-2)(4t+2)$ ?

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Answer 1 · 2018-04-03T02:48:30

The answer is $12t^2-2t-4$ .

First,Multiply the equation $( 4t +2)$ by $(3t)$ and $( 4t +2)$ by $(-2)$ .

Converting it into an equation,

$rArr$ $3t(4t+2) -2(4t+2)$

$rArr$ $12t^2+6t -8t-4$

$rArr$ $12t^2+(6-8)t-4$

$rArr$ $12t^2-2t-4$

$:.$ the answer is $12t^2-2t-4$ .

Let's hope this helps you:)

How do you multiply (3t-2)(4t+2)(3t-2)(4t+2)?