How do you multiply ${(5 x^{- 3} y^{5})}^{2} \cdot 2 x^{- 4} y^{5}$ $(5x ^ { - 3} y ^ { 5} ) ^ { 2} * 2x ^ { - 4} y ^ { 5}$ ?

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Answer 1 · 2018-06-01T12:16:13

$50 x^{- 10} y^{15} or \frac{50 y^{15}}{x^{10}}$ $50x^(-10)y^15 or (50y^15)/x^10$

Expand the bracket first

${(5 x^{- 3} y^{5})}^{2} = 25 x^{- 6} y^{10}$ $(5x^(-3)y^5)^2=25x^(-6)y^10$

$25 x^{- 6} y^{10} \times 2 x^{- 4} y^{5}$ $25x^(-6)y^10xx 2x^-4y^5$

$50 x^{- 10} y^{15} or \frac{50 y^{15}}{x^{10}}$ $50x^(-10)y^15 or (50y^15)/x^10$

How do you multiply (5x ^ { - 3} y ^ { 5} ) ^ { 2} * 2x ^ { - 4} y ^ { 5}(5x−3y5)2⋅2x−4y5(5x ^ { - 3} y ^ { 5} ) ^ { 2} * 2x ^ { - 4} y ^ { 5}?