How do you multiply $[(8,-7), (-4,0)]$ by 3/4?

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Answer 1 · 2018-03-05T09:59:06

seee below

each element will be multiplied by $3/4$

thus the question becomes

$3/4[(8, -7),(-4,0)]$

$=[(6, -21/4),(-3,0)]$

Answer 2 · 2018-03-05T10:07:54

$[(6,-21/4),(-3,0)]$

$"multiply each element in the matrix by "3/4$

$rArr3/4[(8,-7),(-4,0)]=[(6,-21/4),(-3,0)]$

How do you multiply [(8,-7), (-4,0)][(8,-7), (-4,0)] by 3/4?