How do you multiply $e^((5pi )/ 12 ) * e^( pi i )$ in trigonometric form?

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Answer 1 · 2018-07-05T21:31:29

$-e^{{5\pi}/12}$

Using Euler's formula $e^{i\theta}=\cos\theta+i\sin\theta$ as follows

$e^{{5\pi}/12}\cdot e^{\pi i}$

$=e^{{5\pi}/12}(\cos \pi+i\sin\pi)$

$=e^{{5\pi}/12}(-1+i0)$

$=-e^{{5\pi}/12}$

How do you multiply e^((5pi )/ 12 ) * e^( pi i ) e^((5pi )/ 12 ) * e^( pi i ) in trigonometric form?