How do you multiply $e^(( 7 pi )/ 12 i) * e^( 3 pi/2 i )$ in trigonometric form?

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Answer 1 · 2018-04-03T18:51:00

$e^(ix) = cosx + isinx$
$e^(((7pi)/12)i) = cos((7pi)/12) + isin((7pi)/12)$
$e^(((3pi)/2)i) = cos((3pi)/2) + isin((3pi)/2)$

Euler's identity. Multiply the equivalent trigonometric expressions and simplify.

How do you multiply e^(( 7 pi )/ 12 i) * e^( 3 pi/2 i ) e^(( 7 pi )/ 12 i) * e^( 3 pi/2 i ) in trigonometric form?