How do you normalize $<0,8,5>$ ?

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Answer 1 · 2018-05-13T17:46:09

$bb(hat(a))=[(0,(8sqrt(89))/89,(5sqrt(89))/89)]$

A unit vector in the direction of some vector $bba$ is given by:

$bb(hat(a))=(bba)/||bba||$

Let:

$bba=[(0,8,5)]$

$||bba||=sqrt((0)^2+(8)^2+(5)^2)=sqrt(89)$

$:.$

$bb(hat(a))=[(0,(8sqrt(89))/89,(5sqrt(89))/89)]$

How do you normalize <0,8,5> <0,8,5>?