How do you normalize $(-2i + -1j + 2k)$ ?

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Answer 1 · 2018-06-18T06:06:01

The answer is $=<-2/3,-1/3,2/3>$

To normalize a vector $vecu$ , divide the vector by the modulus of the vector

$hatu=vecu/||vecu||$

Here,

$vecu= <-2,-1,2>$

The modulus is

$||vecu|| = ||<-2,-1,2>|| = sqrt((-2)^2+(-1)^2+(2)^2)$

$=sqrt(4+1+4)$

$=sqrt9$

$=3$

Therefore,

$hatu=1/3*<-2,-1,2> = <-2/3,-1/3,2/3>$

How do you normalize (-2i + -1j + 2k) (-2i + -1j + 2k)?