How do you normalize $< 3, 2, 1 >$ $<3, 2, 1>$ ?

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Answer 1 · 2016-02-27T12:02:38

divide the vector by $\sqrt{3^{2} + 2^{2} + 1^{2}} = \sqrt{14}$ $sqrt(3^2+2^2+1^2)=sqrt14$

How do you normalize <3, 2, 1><3,2,1><3, 2, 1>?