How do you normalize $(- 4 i - 5 j + 2k)$ ?

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Answer 1 · 2016-10-25T10:25:22

$1/ (3 sqrt 5) (- 4 i - 5 j + 2k)$

to normalise, divide it by it's magnitide

which is $sqrt( (-4)^2 + (-5)^2 + 2^2) = 3 sqrt 5$

to give

$1/ (3 sqrt 5) (- 4 i - 5 j + 2k)$

How do you normalize (- 4 i - 5 j + 2k) (- 4 i - 5 j + 2k)?