How do you perform the operation in trigonometric form #(cos5+isin5)(cos20+isin20)#?
1 Answer
Jun 19, 2017
Explanation:
#"given"#
#z_1=r_1(costheta_1+isintheta_1)" and "#
#z_2=r_2(costheta_2+isintheta_2)" then"#
#z_1.z_2=r_1.r_2(cos(theta_1+theta_2)+isin(theta_1+theta_2))#
#"here " r_1=r_2=1,theta_1=5,theta_2=20#
#rArr(cos5+isin5)(cos20+isin20)#
#=cos25+isin25#
