How do you prove $(tan)(cos)=csc$ ?

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Answer 1 · 2016-11-18T16:48:23

I think there is a problem with this question

In a rectangular triangle with sides $n,f,h$ where $n=$ near side, $f=$ far side, and $h=$ hypotenuse

$tan=f/n, cos=n/h$

So $tanxxcos=f/cancelnxxcanceln/h=f/h$

And this is the definition of $sin$ , not $csc$

How do you prove (tan)(cos)=csc(tan)(cos)=csc?