How do you simplify $(1 - 2 i) (3 + 4 i)$ $(1-2i)(3+4i)$ ?

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How do you simplify $(1 - 2 i) (3 + 4 i)$ $(1-2i)(3+4i)$ ?

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Answer 1 · 2017-10-01T08:06:16

$11 - 2 i$ $11-2i$

Explanation:

$(1 - 2 i) (3 + 4 i)$ $(1-2i)(3+4i)$
Just Multiply terms
$= (1) (3 + 4 i) - 2 i (3 + 4 i)$ $=(1)(3+4i)-2i(3+4i)$
$= 3 + 4 i - 6 i - 8 i^{2}$ $=3+4i-6i-8i^2$

Using Property $i = \sqrt{-} 1$ $i=sqrt-1$ and $i^{2} = - 1$ $i^2=-1$
$= 3 - 2 i + 8$ $=3-2i+8$
$= 11 - 2 i$ $=11-2i$

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How do you simplify $(1 - 2 i) (3 + 4 i)$ $(1-2i)(3+4i)$ ?

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How do you simplify (1−2i)(3+4i)(1-2i)(3+4i)?

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How do you simplify $(1 - 2 i) (3 + 4 i)$ $(1-2i)(3+4i)$ ?