How do you simplify $10x(x^2-10)$ ?

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Answer 1 · 2015-10-03T02:37:56

$10x(x^2-10)=10x^3-100x$

$10x(x^2-10)$

Apply the distributive property $a(b+c)=ab+ac$ .

$10x(x^2)+10x(-10)$

Apply the exponent rule $a^mxxa^n=a^(m+n)$ .

$10x^(1+2)+10x(-10)=$

$10x^3+10x(-10)=$

$10x^3-100x$

How do you simplify 10x(x^2-10)10x(x^2-10)?