How do you simplify $11/(t^-2) ^-5 times (5t^-4) /t^-4$ ?

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Answer 1 · 2018-04-25T04:01:51

$55/t^10$

Given: $11/(t^-2)^-5 xx (5t^-4)/t^-4$

Use the exponent rule: $(x^m)^n = x^(m*n)$

$11/(t^-2)^-5 xx (5t^-4)/t^-4 = 11/t^10 xx (5cancel(t^-4))/cancel(t^-4)$

$= (11 * 5)/t^10$

$= 55/t^10$

How do you simplify 11/(t^-2) ^-5 times (5t^-4) /t^-411/(t^-2) ^-5 times (5t^-4) /t^-4?