How do you simplify 12x(x2+3)8x(x2+3)+5(x2+3)?

2 Answers
Apr 6, 2018

You can either distribute and combine like terms or you can factor.

Explanation:

I'll show distributing first.

I like to distribute one term at a time then combine them.
12x(x2+3)12x3+36x
8x(x2+3)8x324x
5(x2+3)5x2+15

12x3+36x8x324x+5x2+15

Combine like terms
4x3+12x+5x2+15

Put it in the proper order
4x3+5x2+12x+15

That would be it for distributing.


For factoring, you find a common factor in each term and pull it out.

12x(x2+3)8x(x2+3)+5(x2+3)

Every term is multiplied by (x2+3). Pulling that out of the expression gives you
(x2+3)(12x8x+5)

Then combine like terms
(x2+3)(4x+5)

And that's it. I hope this helps.

Apr 6, 2018

4x3+5x2+12x+15

Explanation:

  • Use the distributive property to simplify each part in parenthesis, then add.

You started with 12x(x2+3)8x(x2+3)+5(x2+3)

Distribute the 12x, -8x, and 5 to the values in parenthesis they are next to:
((12xx2)+(12x3))+((8xx2)+(8x3))+((5x2)+(53))
12x3+36x8x324x+5x2+15

Rearrange so you can combine like terms (list with exponents in descending order):
12x38x3+5x2++36x24x+15

Combine like terms:
4x3+5x2+12x+15

  • Alternatively, because the value in parenthesis is the same (it is x2+3), you can take add the coefficients together and multiply their sum by x2+3 .

You started with 12x(x2+3)8x(x2+3)+5(x2+3)

The coefficients are 12x, -8x, and 5. Add those together. You are able to do that because they are each being multiplied by the same thing (x2+3).
12x+(8x)+5

Combine like terms:
4x+5

Multiply the value you just got (4x+5) by the value each coefficient was being multiplied by in the original problem (x2+3):
(4x+5)(x2+3)

Distributive Property (use the FOIL method):
(4xx2)+(4x3)+(5x2)+(53)

Multiply to find each value in parenthesis:
4x3+12x+5x2+15

Rearrange (list with exponents in descending order):
4x3+5x2+12x+15

There are no like terms to combine, so your answer is 4x3+5x2+12x+15!