So we have
((-15(ab)^2)/(5a^2b))^5
First let's take that first square in the first term, since it's a multiplication the exponent goes to both numbers.
((-15a^2b^2)/(5a^2b))^5
Now we can get rid of any letters that show up equally in top and bottom, we have 2 as on top and 2 in the bottom so they both go, but we only 1 b in the bottom and two on the top, so one of the bs on the top will remain.
((-15b)/5)^5
Now, we simplify the actual numbers, we know 15 = 3*5 so it's just a matter of factorizing and discarding equal factors on top and bottom.
(-3b)^5
Which is easy to compute if you so wish, the letter just gets the exponent, the minus sign continues to be a minus because (-1)*(-1)^2*(-1)^2 = (-1)*1*1=-1, which only leaves us to deal with the 3, but since 3^5 = 3*(3)^2*(3)^2=3*9*9=3*81, we only need to do one multiplication that isn't tabled.
3*81 = 3*80 + 3*1 = 243, so the final expression is
(-3b)^5 or -243b^5