How do you simplify $\frac{15 t^{- 4} t^{3}}{- 3 t^{- 2}}$ $(15t^-4t^3)/(-3t^-2)$ ?

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Answer 1 · 2016-02-15T17:58:46

$= - 5 t$ $= -5 t$

$\frac{15 t^{- 4} t^{3}}{- 3 t^{- 2}}$ $(15t^-4t^3)/(-3t^-2)$

$= (\frac{15}{- 3}) \times \frac{t^{- 4} t^{3}}{t^{- 2}}$ $= (15/-3) xx (t^-4t^3)/(t^-2)$

$= - 5 \times \frac{t^{- 4} t^{3}}{t^{- 2}}$ $= -5 xx (t^-4t^3)/(t^-2)$

As per property:
$1 . \frac{a^{m}}{a^{n}} = a^{m - n}$ $1. color(blue)(a^m/a^n=a^(m-n)$

$2 . a^{m} \times a^{n} = a^{m + n}$ $2. color(blue)(a^m xx a^n=a^(m+n)$

Applying the above to exponents of $t$ $t$ :
$= - 5 \times \frac{t^{- 4} t^{3}}{t^{- 2}}$ $= -5 xx (t^-4t^3)/(t^-2)$

$= - 5 \times \frac{t^{- 4 + 3}}{t^{- 2}}$ $= -5 xx (t^(-4 +3))/(t^-2)$

$= - 5 \times \frac{t^{- 1}}{t^{- 2}}$ $= -5 xx (t^(-1))/(t^-2)$

$= - 5 \times t^{- 1 - (- 2)}$ $= -5 xx t^(-1- (-2))$

$= - 5 \times t^{- 1 + 2}$ $= -5 xx t^(-1+2)$

$= - 5 \times t^{1}$ $= -5 xx t^1$

$= - 5 t$ $= -5 t$

How do you simplify (15t^-4t^3)/(-3t^-2)15t−4t3−3t−2(15t^-4t^3)/(-3t^-2)?