How do you simplify $( 16 - 3r^2 + 4r) - ( 12 - 3r + 2r^2)$ ?

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Answer 1 · 2015-06-15T12:27:17

$=color(blue)( - 5r^2 +7r +4$

$16-3r^2+4r- 12 +3r-2r^2$

grouping like terms :

$=(16- 12) - (3r^2 +2r^2) +(4r +3r)$
$=4 - 5r^2 +7r$
$=color(blue)( - 5r^2 +7r +4$

How do you simplify ( 16 - 3r^2 + 4r) - ( 12 - 3r + 2r^2)( 16 - 3r^2 + 4r) - ( 12 - 3r + 2r^2)?