How do you simplify #(2 1/3+1 2/5)+3 2/3#?

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Answer 1 · 2018-07-07T07:20:12

#37/5#

Given: #(2 1/3 + 1 2/5 ) + 3 2/3#

First switch each mixed number to an improper fraction:

#(2 1/3 + 1 2/5 ) + 3 2/3 = (7/3 + 7/5) + 11/3#

Find a common denominator for #33# and #5: " "15#

Multiply each fraction by #1# to get our common denominator so we can add the fractions:

#(5/5 * 7/3 + 3/3 * 7/5) + 5/5 * 11/3#

#(35/15 + 21/15) + 55/15 = 111/15#

Now reduce, since #1+1+1 = 3# which means #111# is divisable by #3#:

#111/15 -: 3/3 = 37/5#