How do you simplify $(2 - 3 i) + (- 2 - 5 i)$ $(2-3i)+(-2-5i)$ ?

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Answer 1 · 2018-07-28T04:20:01

$- 8 i$ $-8i$

Given that

$(2 - 3 i) + (- 2 - 5 i)$ $(2-3i)+(-2-5i)$

$= 2 - 3 i - 2 - 5 i$ $=2-3i-2-5i$

$= - 8 i$ $=-8i$

Answer 2 · 2018-07-28T06:10:18

$- 8 i$ $-8i$

Even though it is not a variable, for the most part, we can treat the imaginary unit like it is one.

Since we aren't multiplying by a negative, the parenthesis are unnecessary. We simply just add the corresponding parts to get

$- 8 i$ $-8i$ , as $2$ $2$ and $- 2$ $-2$ cancel out.

Hope this helps!

How do you simplify (2-3i)+(-2-5i)(2−3i)+(−2−5i)(2-3i)+(-2-5i)?