How do you simplify $(2ag^2)^4(3a^2g^3)^2$ ?

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Answer 1 · 2018-06-15T04:47:53

$144a^8g^14$

$(2ag^2)^4(3a^2g^3)^2$

First, let's look at $(2ag^2)^4$ . The exponent $4$ applies to everything inside the parenthesis, so:
$2^4 = 16$

$a^4 = a^4$

$(g^2)^4 = g^(2*4) = g^8$

Multiply them all together:
$16a^4g^8$

Now $(3a^2g^3)^2$ :
$3^2 = 9$

$(a^2)^2 = a^(2*2) = a^4$

$(g^3)^2 = g^(3*2) = g^6$

Multiply them all together:
$9a^4g^6$

Now multiply both simplified expressions:
$(16a^4g^8)(9a^4g^6)$

Simplify:
$144a^(4+4)g^(8+6)$

Therefore, the simplified expression is:
$144a^8g^14$

Hope this helps!

How do you simplify (2ag^2)^4(3a^2g^3)^2(2ag^2)^4(3a^2g^3)^2?