How do you simplify ${(- 2 b^{2} c)}^{3}$ $(-2b^2c)^3$ ?

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Answer 1 · 2016-06-14T08:57:02

Remember ${(A \cdot B \cdot C)}^{3} = A^{3} \cdot B^{3} \cdot C^{3}$ $(A*B*C)^3=A^3*B^3*C^3$ and ${(A^{2})}^{3} = A^{2 \cdot 3}$ $(A^2)^3=A^(2*3)$

$= {(- 2)}^{3} \cdot {(b^{2})}^{3} \cdot c^{3} = - 8 b^{6} c^{3}$ $=(-2)^3*(b^2)^3*c^3=-8b^6c^3$

How do you simplify (-2b^2c)^3(−2b2c)3 (-2b^2c)^3?