How do you simplify $(2c^2+2c-12)/(-8+2c+c^2)$ ?

Question

1599 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-04T13:38:56

$(2(c+3))/(c+4)$

$(2c^2+2c-12)/(-8+2c+c^2)$

= $(2(c^2+c-6))/(c^2 +2c-8)" " (larr"common factor of 2")/(larr"re-arrange the terms")$

$=(2(c+3)cancel((c-2)))/((c+4)cancel((c-2))) " "larr$ find factors of quadratics

$=(2(c+3))/(c+4)$

How do you simplify (2c^2+2c-12)/(-8+2c+c^2)(2c^2+2c-12)/(-8+2c+c^2)?