How do you simplify $2 h^{2} \times 3 h^{4}$ $2h^2times3h^4$ ?

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Answer 1 · 2017-01-03T04:43:53

$6 h^{6}$ $6h^6$

When multiplying factors with exponents the coefficients are multiplied normally, and the exponents are ADDED to each other.

$2 \cdot h^{2} \cdot \times 3 \cdot h^{4} = (2 \cdot 3) \cdot h^{2 + 4} = 6 h^{6}$ $2*h^2 *× 3*h^4 = (2 * 3) * h^(2+4) = 6h^6$

Answer 2 · 2017-01-03T04:44:20

$= 6 h^{6}$ $=6h^6$

$2 h^{2} \times 3 h^{4}$ $2h^2 xx 3h^4$

$= (2 \times 3) \cdot (h^{2 + 4})$ $=(2 xx 3)*(h^(2+4))$
$= 6 h^{6}$ $=6h^6$

How do you simplify 2h^2times3h^42h2×3h42h^2times3h^4?