How do you simplify $((2m)/ n^2)^4$ ?

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Answer 1 · 2015-07-13T00:51:03

$((2m)/n^2)^4 = (16m^4)/n^8$

You must apply the outside exponent to everything inside the parentheses.

$((2m)/n^2)^4 = (2^4m^4)/(n^2)^4$

We have to repeat the procedure with the denominator.

$(2^4m^4)/(n^2)^4 = (2^4m^4)/n^8$

So

$((2m)/n^2)^4 = (2^4m^4)/n^8=(16m^4)/n^8$

Answer 2 · 2015-07-13T01:05:51

The answer is $(16m^4)/n^8$ .

$((2m)/(n^2))^4$

$((a)/(b))^x=(a^x)/(b^x)$

$(2m)^4/(n^2)^4$

$(a^x)^y=a^(x*y)$

$(2m)^4/(n^(2*4)$ =

$(2m)^4/n^8$

$(ab)^x=a^xb^y$

$(2^4m^4)/n^8$ =

$(16m^4)/n^8$

How do you simplify ((2m)/ n^2)^4((2m)/ n^2)^4?