How do you simplify $2 \sqrt{12} + 4 \sqrt{27}$ $2sqrt12 + 4sqrt27$ ?

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Answer 1 · 2015-04-13T04:31:17

The answer is $16 \sqrt{3}$ $16sqrt3$ .

In order to add numbers including square roots, the radicands (numbers under the radical) must be the same.

Simplify $2 \sqrt{12} + 4 \sqrt{27}$ $2sqrt 12+4sqrt 27$ .

Factor the square roots.

$2 (\sqrt{4} \cdot \sqrt{3}) + 4 (\sqrt{9} \cdot \sqrt{3})$ $2(sqrt(4)*sqrt(3))+4(sqrt(9)*sqrt(3))$ =

Simplify the square roots.

$2 \cdot 2 \sqrt{3} + 4 \cdot 3 \sqrt{3}$ $2*2sqrt3+4*3sqrt3$ =

$4 \sqrt{3} + 12 \sqrt{3}$ $4sqrt3+12sqrt3$ =

$16 \sqrt{3}$ $16sqrt3$

How do you simplify 2√12+4√272sqrt12 + 4sqrt27?